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Plücker coordinates

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In mathematics Plücker co-ordinates are a way to assign to each line in projective 3-space a point in projective 5-space. Plücker co-ordinates were introduced by Julius Plücker in 1844.

Writing each point in homogeneous co-ordinates the Plücker Mapping is defined as follows:

\begin{matrix} \phi : \mathbb{P}^3 \times \mathbb{P}^3 &\rightarrow& \mathbb{P}^5 \\ (x_0:x_1:x_2:x_3) \times (y_0:y_1:y_2:y_3) &\mapsto& (p_{01}:p_{02}:p_{03}:p_{12}:p_{13}:p_{23}) \end{matrix}

where pij = xiyjxjyi

This can be expressed in a more compact form. Consider the matrix:

\begin{pmatrix} x_0 & x_1 & x_2 & x_3 \\ y_0 & y_1 & y_2 & y_3 \end{pmatrix}

Then pij is just seen to be the determinant of the 2x2 matrix consisting of the ith and jth columns.

Contents

1 Line geometry

Properties of the Plücker mapping

For the following arguments, X = (x_0:x_1:x_2:x_3) \in \mathbb{P}^3, Y = (y_0:y_1:y_2:y_3) \in \mathbb{P}^3 and \phi(X,Y) = (p_{01}:p_{02}:p_{03}:p_{12}:p_{13}:p_{23}) \in \mathbb{P}^5 as defined above.

The Plücker mapping is well defined

This is only true for X \ne Y.

First, we notice that not all the pij are zero ( (0:0:0:0:0) is not a point of \mathbb{P}^5 ). This is true because if y_{k_1} is a nonzero component of y, then there exists k2 with k_2 \ne k_1 with x_{k_2} \ne \frac{x_{k_1}}{y_{k_1}}y_{k_2} (otherwise X = \frac{x_{k_1}}{y_{k_1}}Y = Y \in \mathbb{P}^3).

Then the component of φ(X,Y), p_{k_1k_2} = x_{k_1}y_{k_2} - x_{k_2}y_{k_1} = y_{k_1}( \frac{x_{k_1}}{y_{k_1}}y_{k_2} - x_{k_2} ) \ne 0.

Next, if X = X^\prime and Y = Y^\prime \in \mathbb{P}^3 then X^\prime =\lambda X and Y^\prime = \mu Y.

So \phi(X^\prime,Y^\prime) = (p_{01}^\prime:p_{02}^\prime:p_{03}^\prime:p_{12}^\prime:p_{13}^\prime:p_{23}^\prime)

where p_{ij}^\prime = x_i^\prime y_j^\prime - x_j^\prime y_i^\prime = \lambda x_i \mu y_j - \lambda x_j \mu y_i = \lambda \mu( x_i y_j - x_j y_i ) = \lambda \mu p_{ij} so

\phi(X^\prime,Y^\prime) = \lambda \mu (p_{01}:p_{02}:p_{03}:p_{12}:p_{13}:p_{23}) = (p_{01}:p_{02}:p_{03}:p_{12}:p_{13}:p_{23}) = \phi( X, Y ) \in \mathbb{P}^5.

So φ is well defined if X \ne Y \in \mathbb{P}^3.

The Plücker mapping takes lines to points

If X^\prime and Y^\prime are on the line determined by X and Y in \mathbb{P}^3 then

X^\prime = ( x_0 + ry_0: x_1 + ry_1: x_2 + ry_2: x_3 + ry_3 ) and

Y^\prime = ( x_0 + sy_0: x_1 + sy_1: x_2 + sy_2: x_3 + sy_3 ) for some r,s with r \ne s.

Then the ijth component of \phi( X^\prime, Y^\prime ) is (xi + ryi)(xj + ryj) − (xj + ryj)(xi + syi). Expanding, this product, we have

(xi + ryi)(xj + ryj) − (xj + ryj)(xi + syi) = (sr)(xiyjyjxi) = (sr)pij

So \phi( X^\prime, Y^\prime ) = (s-r) \phi( X,Y ) = \phi( X,Y ) \in \mathbb{P}^5

So φ takes points on the same line in \mathbb{P}^3 to the same point in \mathbb{P}^5.

For the other direction, we wish to show that if \phi( X,Y ) = \phi( X^\prime, Y^\prime ) = ( p_{01}:p_{02}:p_{03}:p_{12}:p_{13}:p_{23} ) then (X,Y) and (X^\prime,Y^\prime) determine the same line in \mathbb{P}^3.

This follows easily from a simple observation:

\begin{matrix} y_0X - x_0Y & = & ( 0: x_1y_0 - x_0y_1: x_2y_0 - x_0y_2 : x_3y_0 - y_3x_0 ) = ( 0: -p_{01} : -p_{02} : -p_{03} ) \\ y_0^\prime X^\prime - x_0^\prime Y^\prime & = & ( 0: x_1^\prime y_0^\prime x_0^\prime y_1^\prime : x_2^\prime y_0^\prime - x_0^\prime y_2^\prime : x_3^\prime y_0^\prime - x_0^\prime y_3^\prime ) = ( 0: -p_{01} : -p_{02} : -p_{03} ) \\ \end{matrix}

Similar calculations yield that y_iX -x_iY = y_i^\prime X^\prime - y_i^\prime Y^\prime

But yiXxiY is on the line defined by X,Y and y_i^\prime X^\prime - x_i^\prime Y^\prime are on the line defined by X^\prime,Y^\prime. Since the lines have more than two points in common, they must be the same.

So we can think of φ(X,Y) as the line (in \mathbb{P}^3) through X and Y.

The image of the Plücker map

The image of the Plücker map in \mathbb{P}^5 is called the Plücker quadric.

Define C \subset \mathbb{P}^5 by C:{(p01:p02:p03:p12:p13:p23) | p01p23p02p13 + p03p12 = 0}

A direct calculation yields that the image of a line (p01:p02:p03:p12:p23) satisfies the equation p01p23p02p13 + p03p12 = 0

So the image of φ is contained in C.

For a point (p01:p02:p03:p12:p13:p23) in C, one of the components must be nonzero. So we suppose p_{01} \ne 0 otherwise we can change coordinates.

Now let X = (0:p01:p02:p03) and Y = (p01:0: − p12: − p13)

Then \phi( X,Y ) = (-p_{01}^2:-p_{01}p_{02}:-p_{01}p_{03}:-p_{01}p_{12}:-p_{01}p_{13}:-p_{02}p_{13}+p_{12}p_{03} ) using our relation p01p23p02p13 + p03p12 = 0 we have p02p13 + p12p03 = − p01p23 so \phi( X, Y ) = (-p_{01}^2:-p_{01}p_{02}:-p_{01}p_{03}:-p_{01}p_{12}:-p_{01}p_{13}:-p_{01}p_{23} ) = (p_{01}:p_{02}:p_{03}:p_{12}:p_{13}:p_{23})

So the Plücker map maps onto C.

Uses of the Plücker map

Using the Plücker Map we can think of certain points in \mathbb{P}^5 as lines in \mathbb{P}^3. We can use this characterization to easily find certain classes of lines.

  • If we want all the lines through the point (x_0:x_1:x_2:x_3) \in \mathbb{P}^3, a direct calculation yields that these are just the lines with Plucker co-ordinates (p01:p02:p03:p12:p13:23) where x0x2p13x0x1p23x1x3p02 = 0
  • If we want all the lines in the plane x0 = a1x1 + a2x2 + a3x3, another calculation shows that these are just the points with Plucker co-ordinates satisfying a1p01 + a2p02 + a3p03 = 0

Line geometry

During the nineteenth century, line geometry was studied quite intensively. In terms of the formulation given above, this is a description of the intrinsic five-dimensional geometry on the quadric.

Other formulations of Plücker co-ordinates

Plucker co-ordinates can be formulated more generally using the ideas of multilinear algebra and the wedge product. This leads to a simple formulation of the generalisation of the Plücker mapping.

A Plücker map is a map π

\begin{matrix} \pi : Gr(n,N) &\rightarrow& \mathbb{P}(\wedge^n\mathbb{C}^N)\\ span( v_1, \ldots, v_n ) &\mapsto& \mathbb{C}( v_1 \wedge \ldots \wedge v_n )\\ \end{matrix}

where Gr(n,N) is the Grassmannian, i.e. the space of all n-dimensional subspaces of an N-dimensional vector space. The map described above is the particular case where n = 1, N = 3.

In the general context, the Grassmannian can be completely characterised as an intersection of quadrics, each coming from a relation on the Plücker co-ordinates that derives from linear algebra.

Wikipedia (http://en.wikipedia.org/wiki/Main_Page) Line_geometry (http://en.wikipedia.org/wiki/Line_geometry) version history (http://en.wikipedia.org/w/index.php?title=Line_geometry&action=history) GNU Free Documentation Lizenz (http://en.wikipedia.org/wiki/Wikipedia:Text_of_the_GNU_Free_Documentation_License) CC-by-sa (http://creativecommons.org/licenses/by-sa/2.5/)

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